打卡|Twitter|Find Missing Numbers in an Array

2021-01-18 IT信息教室
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Given an array of integers of size n, where all elements are between 1 and n inclusive, find all of the elements of [1, n] that do not appear in the array. Some numbers may appear more than once.

給定一個有 n 的元素的正整數列表，列表中的元素是 1 到 n 的正整數，找到 [1, n] 區間中缺少的正整數，列表中可能出現相同的數值。

Test Case:

Input1: nums = [4, 6, 2, 6, 7, 2, 1]Output1:  [3, 5]
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參考代碼（Python 3）：
class Solution:    def findDisappearedNumbers(self, nums):        for idx in range(len(nums)):            index = abs(nums[idx]) - 1            nums[index] = -abs(nums[index])        return [idx for idx, num in enumerate(nums, start = 1) if num > 0]    nums = [4, 6, 2, 6, 7, 2, 1]result = Solution().findDisappearedNumbers(nums)print(result)print(''.join(str(result).split()))
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